Matematika Q. mth~

Terlampir di gambar_.​

Q. mth~

Terlampir di gambar_.​
  • Tinggi trapesium

[tex] \tt = \sqrt{ {20}^{2} - {((31 - 7) \div 2)}^{2} } [/tex]

[tex] \tt = \sqrt{400 - {(24 \div 2)}^{2} } [/tex]

[tex] \tt = \sqrt{400 - {12}^{2} } [/tex]

[tex] \tt = \sqrt{400 - 144} [/tex]

[tex] \tt = \sqrt{256} [/tex]

= 16 cm

  • Luas

[tex] \tt = \frac{(a \: + \: b) \: \times \: t}{2} [/tex]

[tex] \tt = \frac{(31 \: + \: 7) \times 16}{2} [/tex]

[tex] \tt = \frac{38 \: \times \: 16}{2} [/tex]

[tex] \tt = \frac{608 \: {cm}^{2} }{2} [/tex]

= 304 cm²

[tex]\purple{\boxed{\blue{\boxed{\green{\star{\orange{\ \: \: \mathcal{JK} \: \: \: {\green{\star}}}}}}}}} [/tex]

Penjelasan dengan langkah-langkah:

tinggi trapesium..

= √(20² - ([31-7]/2)²)

= √(400 - (24/2)²)

= √(400 - 12²)

= √(400 - 144)

= √256

= 16 cm

Luas = (7 + 31)/2 x 16

= 38/2 x 16

= 19 x 16

= 304 cm²

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